gcmol373
gcmol373
12-08-2021
Mathematics
contestada
A= 12b1+b2h ; solve for b1
Respuesta :
snowmaharani614
snowmaharani614
12-08-2021
Answer:
b1 = 2A/h – b2
Step-by-step explanation:
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In other words, which equations have equivalent expressions? true. 2t + 3t = 6t y + y + y = y(1 + 1 + 1) 3(2 + x) = 6 + 3x 2a + 2b = 4ab x + 3 = 4x
