9514 1404 393
Answer:
x = 5/8 ± i(√7)/8
Step-by-step explanation:
Comparing the given equation to the standard form for the quadratic, ...
ax² +bx +c = 0
we see that we have a=4, b=-5, c=2. This lets us use the quadratic formula to find the solutions:
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-(-5)\pm\sqrt{(-5)^2-4(4)(2)}}{2(4)}=\dfrac{5\pm\sqrt{-7}}{8}\\\\x=\left\{\dfrac{5}{8}-\dfrac{\sqrt{7}}{8}i,\dfrac{5}{8}+\dfrac{\sqrt{7}}{8}i\right\}[/tex]
