Respuesta :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

let's solve for x :

  • [tex](x - 3)(x + 5) = 9[/tex]

  • [tex] {x}^{2} + 5x - 3x - 15 = 9[/tex]

  • [tex] {x}^{2} + 2x - 15 - 9 = 0[/tex]

  • [tex] {x}^{2} + 2x - 24 = 0[/tex]

  • [tex] {x}^{2} + 6x - 4x - 24 = 0[/tex]

  • [tex] x(x + 6) - 4(x + 6) = 0[/tex]

  • [tex](x + 6)(x - 4) = 0[/tex]

so,

  • [tex]x = - 6[/tex]

or

  • [tex]x = 4[/tex]

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