clintonetti clintonetti
  • 03-01-2017
  • Physics
contestada

A child lifts a 5.0-newton toy to a height of 0.50 meters. How much work is done on the toy?

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naveenranjeet98
naveenranjeet98 naveenranjeet98
  • 03-01-2017
Work done=mgh
W=force*height
W=5N*0.50mts
W=2.5joule
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Аноним Аноним
  • 03-01-2017
you can use the formula

Work = force x distance

therefore, 

W= (5.0)(.50)
W = 2.5 joules

hope this helps :)
Answer Link

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