dakotaarrington dakotaarrington
  • 02-03-2022
  • Chemistry
contestada

FeCl3 + NaOH → Fe(OH)3 + NaCl

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DᴀʀᴋPᴀʀᴀᴅᴏx
DᴀʀᴋPᴀʀᴀᴅᴏx DᴀʀᴋPᴀʀᴀᴅᴏx
  • 02-03-2022

[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

Here's the solution ~

The required balanced equation is :

[tex]\qquad \sf  FeCl_3 + 3 \: NaOH \dashrightarrow Fe(OH)_3 + 3 \: NaCl[/tex]

Reactant Side :

  • Iron (Fe) = 1

  • Sodium (Na) = 3

  • Oxygen (O) = 3

  • Hydrogen (H) = 3

  • Chlorine (Cl) = 3

Product side :

  • Iron (Fe) = 1

  • Sodium (Na) = 3

  • Oxygen (O) = 3

  • Hydrogen (H) = 3

  • Chlorine (Cl) = 3

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