Note:- For tabular way solution refer to the first one .Here I do a simple way to let you understand better
Let's do
Balanced equation is given by
[tex]\\ \rm\Rrightarrow 4Fe+3O_2\longrightarrow 2Fe_2O_3[/tex]
- 3mols of O_2 produces 2 mol Fe_2O_3
- 1 mol O_2 produces 2/3=0.6mol Fe_2O_3
Moles of O_2:-
Moles of Fe_2O_3
Mass of Fe_2O_3
