Answer:
[tex]\frac{19+8\sqrt{3} }{13}[/tex]
Step-by-step explanation:
Given :
- [tex]\frac{4+\sqrt{3} }{4-\sqrt{3} }[/tex]
Multiply using the reciprocal :
- [tex]\frac{4+\sqrt{3}(4+\sqrt{3}) }{4-\sqrt{3}(4+\sqrt{3}) }[/tex]
- [tex]\frac{16+8\sqrt{3}+3 }{16-3}[/tex]
Simplify numerator and denominator :
- [tex]\frac{19+8\sqrt{3} }{13}[/tex]
