Respuesta :

loneguy

[tex]\text{Given that,}~ f(x) = 2x-3\\\\\text{Now,}\\\\~~\dfrac{f(x+h)-f(x)}{h}\\\\\\=\dfrac{2(x+h) -3 - (2x-3)}{h}\\\\\\=\dfrac{2x+2h-3 -2x +3 }{h}\\\\\\=\dfrac{2h}{h}\\\\\\=2[/tex]

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