The equation of the table is y = 28x
How to write equation of a linear table?
The slope intercept equation of a linear equation is as follows:
y = mx + b
where
Therefore, let's find the slope using (1, 28)(2, 56)
m = slope = 56 - 28 / 2 - 1 = 28
Therefore, let's find the y-intercept as follows:
using (1, 28)
28 = 28(1) + b
b = 28 - 28
b = 0
Hence, the equation of the table is y = 28x
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