There are 5/9 groups in 1
6 divided by 9/5 is 3 1/3.
An improper fraction is a non integer where the numerator is greater than the denominator. An example is 9/5.
In order to determine the the number of groups of 9/5 that are in 1, divide 1 by 9/5
1 ÷ 9/5
1 × 5/9
9/9 × 5/9 = 5/9
6 ÷ 9/5
6 × 5/9 = 10 / 3 = 3 1/3
To learn more about the division of fractions, please check: https://brainly.com/question/25779356
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