Answer:
Hello,
Step-by-step explanation:
[tex]9x^3+2x-4=(3x-2)*(3x^2+2x+2) \\Remainder\ is\ 0\\\\if\ x \neq \dfrac{2}{3} \\\\\dfrac{9x^3+2x-4}{3x-2}=\dfrac{(3x-2)*(3x^2+2x+2) }{3x-2} =3x^2+2x+2[/tex]
