Answer:
Solve for x: [tex]x = \frac{3y+1}{4y-2}[/tex]
Evaluate x for y = 1: [tex]x = 2[/tex]
Step-by-step explanation:
[tex]Original:y=\frac{2x+1}{4x-3}\\Multiply\ out\ the\ denominator:(4x-3)*y = 2x+1\\Distribute: 4xy - 3y = 2x+1\\Group\ Like\ Terms:4xy-2x = 3y+1\\Factor\ Out\ x: x(4y-2) = 3y+1\\Divide\ to\ get\ x\ alone:x = \frac{3y+1}{4y-2}\\\\Plug\ in\ the\ value\ for\ y:x = \frac{3(1)+1}{4(1)-2}\\Multiply:x = \frac{3+1}{4-2}\\Add:x = \frac{4}{2}\\Simplify/Divide:x=2[/tex]
