We have the following:
[tex]2x+4y=8[/tex]solving for y:
[tex]\begin{gathered} \frac{2}{4}x+\frac{4}{4}y=\frac{8}{4} \\ \frac{1}{2}x+y=2 \\ y=-\frac{1}{2}x+2 \end{gathered}[/tex]now, x- intercept is when y is equal to 0, therefore
[tex]\begin{gathered} 0=-\frac{1}{2}x+2 \\ \frac{1}{2}x=2 \\ x=2\cdot2 \\ x=4 \end{gathered}[/tex]y-intercept is when x is equal to 0, therefore
[tex]\begin{gathered} y=-\frac{1}{2}\cdot0+2 \\ y=2 \end{gathered}[/tex]The answer is:
x - intercept = (4, 0)
y - intercept = (0, 2)
