geometric goes liket his
[tex]a_n=a_1(r)^{n-1}[/tex]
given
a1=15
r=1/3
find a4 or 4th term
[tex]a_4=15( \frac{1}{3} )^{4-1}[/tex]
[tex]a_4=15( \frac{1}{3} )^{3}[/tex]
[tex]a_4=15 (\frac{1}{27})[/tex]
[tex]a_4=\frac{15}{27}[/tex]
[tex]a_4=\frac{5}{9}[/tex]
4th term is 5/9
