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11-05-2017
Mathematics

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use chain rule to show that d(4cos2x)/dx=-8sin2x

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LammettHash LammettHash

12-05-2017

[tex]\dfrac{\mathrm d(4\cos2x)}{\mathrm dx}=4\dfrac{\mathrm d(\cos2x)}{\mathrm dx}=-4\sin2x\dfrac{\mathrm d(2x)}{\mathrm dx}=-8\sin2x[/tex]

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