reganlynn33
reganlynn33 reganlynn33
  • 01-06-2017
  • Chemistry
contestada

If you start witg 14.8g of C3H8 and 3.44g of O2, determine the limiting reagent

Respuesta :

fatouramjaun
fatouramjaun fatouramjaun
  • 01-06-2017
firstly write down the equation:

C3H8 + 5O2 = 3CO2 + 4H20


THEN Calculate the number of mole of each of them
ME OF C3H8 =44
n(C3H8) = (14.8) / 44 =0.336
n(O2) =x (calculate it )

do the same for oxygen then
followed by that

use mole ratio 1 mole of C3H8 react with 5 mole of O2,

BUT  YOU USE ONLY x MOLE OF O2\

if u still have any problem please feel free...
Answer Link

Otras preguntas

What is subject questions?
Help , am still confused
15. BCD are two similar rectangles. AGD and In the figure, AEFG and ABCD are two similar rectan AEB are straight lines. If AE: AB= 3:5, find the ratio o of the
What is the improper fraction for 1/3?
Which could be a pathway of food through an ecosystem? O autotroph - heterotroph – heterotroph autotroph - autotroph – heterotroph heterotroph - autotroph - aut
Can someone help me answer this question? “Describe the ways in which earths “spheres” overlap each other”
Factor this trinomial completely. 2x + 10x + 8
Who is the president of the United States
expand, answer should be a polynomial in standard form (5a+2)(a+4)=
Question 6 3.2 pts _1. The diagram is not to For the parallelogram, if _2= -20 and 24 = 3x - 11.find scale 16 174 164