arico2805
arico2805 arico2805
  • 13-06-2017
  • Chemistry
contestada

If there are 40 mol of NBr3 and 48 mol of NaOH , what is the excess reactant ?

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dec77cat dec77cat
  • 13-06-2017
2NBr₃ + 3NaOH = N₂ + 3HOBr + 3NaBr
40 mol    48 mol

NBr₃:NaOH = 2:3

40:48 = 2:2.4 = 2.5:3

NBr₃ is the excess reactant
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amovoce
amovoce amovoce
  • 30-06-2020

Answer:

NBr3

Explanation:

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