derrickharris64 derrickharris64

15-06-2017
Mathematics

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5. Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0

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Banabanana Banabanana

15-06-2017

–4j² + 3j – 28 = 0
D = b² - 4ac = 3² - 4*(-4)*(-28) = 9 - 448 = -439
D<0 ⇒ j ∈ ∅
No solutions

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