Respuesta :

[tex]\bf f(x)=y=\cfrac{4x-3}{2}\qquad inverse\implies x=\cfrac{4y-3}{2}\impliedby \begin{array}{llll} first\ switch\\ the\ variables\\ then\ solve\\ for\ "y" \end{array} \\\\\\ 2x=4y-3\implies 2x+3=4y\implies \cfrac{2x+3}{4}=y=f^{-1}(x)[/tex]