pranathisaikotha pranathisaikotha
  • 12-01-2024
  • Mathematics
contestada

Radicals stuff
(√6-√3x) (√6-√3x)

Respuesta :

bennguyenphu1 bennguyenphu1
  • 12-01-2024
Its pretty simple because you can just cancel the square root with both numbers multiplied on each other.
answer is: 6-3x
Answer Link
Mickeym175
Mickeym175 Mickeym175
  • 12-01-2024

Answer:

[tex]6-2\sqrt{18x} +3x[/tex]

Step-by-step explanation:

[tex](\sqrt{6} -\sqrt{3x} )(\sqrt{6} -\sqrt{3x} )[/tex]

Distribute

[tex]6-\sqrt{6} \sqrt{3x} -\sqrt{6} \sqrt{3x} +3x[/tex]

Simplify

[tex]6-\sqrt{6*3x} -\sqrt{6*3x} +3x\\6-\sqrt{18x} -\sqrt{18x} +3x[/tex]

[tex]6-2\sqrt{18x} +3x[/tex]

I hope this helps

Answer Link

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