hmm
x+x>x can be rewritten as
2x>x
when is it false?
simple way is for us to solve
2x=x or
2x<x
for 2x=x, x=0 for it to be false
for 2x<x, x<0 for it to be false
so any number that is 0 or negative will disprove it
ok, I pick -3
x+x>x
(-3)+(-3)>-3
-6>-3
false
