nickfitz1005 nickfitz1005
  • 13-10-2017
  • Mathematics
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find the center and radius for the circle, given the equation: x2+16x+y2-6y=-24

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caylus
caylus caylus
  • 13-10-2017
Hello,

[tex]x^2+16x+y^2-6y=-24\\\\ x^2+2*8*x+64+y^2-2*3*y+9-64-9=-24\\\\ (x+8)^2+(y-3)^2=49\\\\ [/tex]
Center=(-8,3), radius=7
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