Respuesta :

([x]12+ [y]12) = f([x+y}12) = [x+y]4 = [x}4+ [y]4 = f([x]12)+ f([y]12) 
([x]12+ [y]12) = f([x+y}12) = [x+y]4 = [x}4+ [y]4 = f([x]12)+ f([y]12) I searched it up.