KEITH555
KEITH555 KEITH555
  • 11-11-2017
  • Mathematics
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use distributive law to factor 3+27b+6c check by multiplying

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Аноним Аноним
  • 11-11-2017
[tex]3+27b+6c[/tex] 

    [tex]GCF = 3[/tex] 

[tex]3( \dfrac{3}{3} + \dfrac{27b}{3} + \dfrac{6c}{3}) [/tex]  [tex]\text{Factor out the GCF}[/tex] 

[tex]3(1+9b+2c) [/tex]   [tex]\text{Simplify each term in parentheses}[/tex]
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