Answer:
[tex]Molec_{H_2O}=3.16x10^{22}MolecH_2O[/tex]
Explanation:
Hello,
In this case, by applying the Avogradro's number as a relationship between moles and molecules, we obtain:
[tex]Molec_{H_2O}=0.0524molH_2O*\frac{6.022x10^{23}MolecH_2O}{1molH_2O} \\Molec_{H_2O}=3.16x10^{22}MolecH_2O[/tex]
Best regards.