savvy5 savvy5
  • 15-12-2015
  • Mathematics
contestada

Tyler is thinking of a number that is divisible by 2 and by 3. By which of the following numbers must Tyler's number also be divisible?

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K3v
K3v K3v
  • 15-12-2015
by 6, because 6/2=3, 6/3=2, 6/6=1 12/6=2, etc. 
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