14-02-2018
Mathematics

contestada

find the product (2x^2+tv)(3x^2-3tv)

find the product 2x2tv3x23tv class=

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14-02-2018

= 2x^2 * 3x^2 + - 2x^2 * 3tv + 3x^2tv - 3t^2v^2

= 6x^4 - 6x^2tv + 3x^2tv - 3t^2v^2

= 6x^4 - 3x^2tv - 3t^2v^2

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