Noahlsmith76 Noahlsmith76

15-03-2018
Mathematics

contestada

What is the inverse of x/(x-1)

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15-03-2018

[tex]y= \frac{x}{x-1} \\ \\ y(x-1)=x \\ xy-y=x \\ xy-x=y \\ x(y-1)=y \\ \\ x= \frac{y}{y-1} \;\;\;\Rightarrow f^{-1}(x)= \dfrac{x}{x-1}[/tex]

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