–2x + 6. (f – g)(x) = f (x) – g(x). = [3x + 2] – [4 – 5x]. = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x – 2. (f × g)(x) = [f (x)][g(x)]. = (3x + 2)(4 – 5x). = 12x + 8 – 15x2 – 10x ... of the functions at x = 2 and then work from there. It's probably simpler in this case to evaluate first, so: f (2) = 2(2) = 4. g(2) = (2) + 4 = 6. h(2) = 5 – (2)3 = 5 – 8 = –3
