Respuesta :

[tex]\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \boxed{a^{log_a x}=x}\\\\ -------------------------------\\\\ log_2(x+4)-5=17\implies log_2(x+4)=22\implies 2^{log_2(x+4)}=2^{22} \\\\\\ x+4=2^{22}\implies x=2^{22}-4\implies x=4194300[/tex]

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